We'll use that fact later. Array.apply(null, [undefined, undefined, undefined]) is equivalent to Array(undefined, undefined, undefined), which produces a three-element array and assigns undefined to each element. How can you generalize that to N elements? Consider how Array() works, which goes something like this:
The array structure has stricter rules than a list or np.array, and this can reduce errors and make debugging easier, especially when working with numerical data.
The third way of initializing is useful when you declare an array first and then initialize it, pass an array as a function argument, or return an array. The explicit type is required.
An illustration. Suppose that array contains three integers, 0, 1, 2, and that i is equal to 1. array[i]++ changes array[1] to 2, evaluates to 1 and leaves i equal to 1. array[i++] does not modify array, evaluates to 1 and changes i to 2. A suffix operators, which you are using here, evaluates to the value of the expression before it is ...
The OP was asking 'Array.size () vs Array.length'. From the previous discussions, it was make clear, that the 'size' Function is not part of standard JavaScript but implemented by libraries.
This function returns an array regardless of the size of the range. Ranges will return an array unless the range is only 1 cell and then it returns a single value instead. This function will turn the single value into an array (1 based, the same as the array's returned by ranges) This answer improves on previous answers as it will return an array from a range no matter what the size. It is ...
Of course, if your array is sorted you could do a binary-search instead. Or if each value in the array is always unique you could use a map-based approach instead.
